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90000=10x^2
We move all terms to the left:
90000-(10x^2)=0
a = -10; b = 0; c = +90000;
Δ = b2-4ac
Δ = 02-4·(-10)·90000
Δ = 3600000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3600000}=\sqrt{360000*10}=\sqrt{360000}*\sqrt{10}=600\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-600\sqrt{10}}{2*-10}=\frac{0-600\sqrt{10}}{-20} =-\frac{600\sqrt{10}}{-20} =-\frac{30\sqrt{10}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+600\sqrt{10}}{2*-10}=\frac{0+600\sqrt{10}}{-20} =\frac{600\sqrt{10}}{-20} =\frac{30\sqrt{10}}{-1} $
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